You know it's time for a new car when...
Yeah, these are unmistakeable.
Review this Show | 15 Reviews | Need Help Listening? View Call Details
Tommy spills a basket of eggs. What's the smallest number possible? Find out!
From Ray's dining and dancing series: why was he still hungry, even after going to the restaurant? Find out!
How you know when it's time to trade in your car, part two.
Login or Register to rate and post comments
Show Review - 425
by ttrikalinShow Review - 429
by Artie DShow Review - 431
by AnonymousShow Review - 434
by AnonymousShow Review - 435
by RossShow Review - 717
by datribbleWall vs. Car Issue
by metmanI think that Wolfgang oversimplified the crash issue. If change in momentum was the only factor, every stop sign would be a catastrophe. Time must be considered as factor for damage and injury. Relative speed at impact favors the wall option and energy absorbed by deformation will favor the oncoming car as the choice.
An Observation
by RossGreat show, as always.
Favorite Moment: I'd just like to point out that when you were talking to Forrest from Sacramento, one of you asked him when winter ends. He responded, "End of February." One of you then asked, "And when pray tell does it start?" to which the other of you quipped, "About January!" Forrest, now answering seriously, said, "Around Christmas." I laughed when you guys seemed not to notice that this happens to be...right around January!
You need a new professor
by AnonymousDisregarding any theories about elasticity of the wall or the other car and assuming all things created equal (perfect, elastic collision) just to make the math easy, we'll examine why you need a new professor. And I hate to say this because I had some excellent physics professors, but you should find an engineer. Ok, I didn't hate it that much... In using the momentum (P) as the basis of Wolfgang's theory, he failed to realize that momentum of a system of particles (i.e. car A and car B) is the vector sum of all the momenta. Forces will be equal regardless of your frame of reference, therefore if we hold car B stationary, car A will appear to be oncoming at twice the original speed with twice the momentum. This problem has to be evaluated as a system of both vehicles and can't be simplified to just one vehicle. The energy balance doesn't work if you remove the second vehicle. Your original evaluation was correct: The force of car A (with xmass and yvel) impacting car B (also with xmass and yvel) is equal to car A (with xmass and 2*yvel) impacting an immovable wall as seen from car A.
This show runs worse than my car
by rickahyattI try to download the "Watch a clip" (Where's the option for the whole show?) and a little box appears and a giant "Q" highlights and goes dim, over and over again, saying something about have went somewhere and then STOPPED. Worse than my car.
Favorite Moment: Will be when the damn thing runs!
Pages